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Single Static Assignment

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The sum of least number of temporary variables and total variables required to create a three address code in single static assignment form for the expression
a*b + c/d + e-f is .??

( Can anyone explain how the answer is 16???  )
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t1=a*b;

t2=c/d;

t3=t1+t2;

t4=t3+e;

t5=t4-f;

 

5 temporary variables used while 6 are already there (a,b,c,d,e,f)

total variables=11;

sum of temporary and total=5+11=16
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