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A priority queue is implemented as a Max-Heap. Initially, it has $5$ elements. The level-order traversal of the heap is: $10, 8, 5, 3, 2$. Two new elements $1$ and $7$ are inserted into the heap in that order. The level-order traversal of the heap after the insertion of the elements is:

1. $10, 8, 7, 5, 3, 2, 1$
2. $10, 8, 7, 2, 3, 1, 5$
3. $10, 8, 7, 1, 2, 3, 5$
4. $10, 8, 7, 3, 2, 1, 5$
edited | 1.2k views

ans is (D)....whenever we insert an element in heap,it will always inserted in last level from left to right..so here we insert element $1$ and $7$ as a child of node $5$.then we perform heapify algorithm until we get the min/max heap..so here finally in above question we get the heap whose level order traversal is $10,8,7,3,2,1,5$

Initial heap:

After insert of $1$

After insert of $7$

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–1

"A priority queue is implemented as a Max-Heap"  has no use ??? dont you think A option is correct since after insertion queue will remain be priority queue .

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How did you deduce from the question that Heapify wasn't performed?

Don't you have to adjust the heap after each insertion?
+1 vote

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