1 votes 1 votes How many 2-input multiplexers are required to construct a 2^10-input multiplexer? Digital Logic digital-logic multiplexer + – Ashish Roy asked Jul 11, 2017 Ashish Roy 2.0k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 3 votes 3 votes To construct $2^{10}$x1 MUX using 2x1 MUX: 1024/2 = 512 512/2=256 256/2=128 128/2=64 64/2=32 32/2=16 16/2=8 8/2=4 4/2=2 2/2=1 Now add all the values 1 + 2 + 4 + 8 + .............. +512 = 1023 Hence 1023 should be answer! Manu Thakur answered Jul 11, 2017 selected Jul 13, 2017 by Vijay Thakur Manu Thakur comment Share Follow See all 0 reply Please log in or register to add a comment.