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+1 vote
Let transmission time  = 1ms , propagation delay = 1 ms and we have used TDM access control method.

What is the efficiency of the network and what is throughput if we are given a bandwidth of 4mbps.

If we want to have N number of nodes/stations in this network and each requires 2kbps of bandwidth. Then what is the value of N ?
asked in Computer Networks by Loyal (4.7k points) | 143 views
efficiency = 50%

throughput = 2mbps

# stations=1000... ????
efficiency is correct but i am confused with # of stations.

Should we use effective Bandwidth( 2mbps) or given bandwidth( 4 mbps) to find number of stations.

Why should we use 2mbps in calculation and why not 4mbps?

2 Answers

0 votes
TDM is one of simplest method for access control. In TDM a fixed time slot is allocated to all node in round robin manner.

so efficiency in TDM = Tt/(Tt+Tp) where Tt is Transmission delay and Tp is Propagation delay

efficiency n = 1/(1+1) = 0.5 %

so throughput / link utilization = 0.5 * bandwidth = 0.5 * 4 = 2 mbps  (i.e. only 2 mbps out of 4 mbps is utilized for channel )

if one station require 2kbps then maximum ( 2mbps/2kbps) = 1000 stations can be there in the link.
answered by (261 points)
I am confused with the number of stations  connected to network i.e. 1000 as answered. My confusion is that if at a time only one station is allowed access to the link then why can it not use the complete usable bandwidth of 2 mbps and why can we not have infinite number of stations in such a link?
0 votes
efficiency = 50%


answered by (127 points)

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