1 votes 1 votes simplify A B' C' + D' C + [ ( A' + B + C)(D + C')] A_i_$_h asked Jul 19, 2017 • edited Jul 19, 2017 by A_i_$_h A_i_$_h 368 views answer comment Share Follow See all 3 Comments See all 3 3 Comments reply joshi_nitish commented Jul 19, 2017 reply Follow Share ~A + B + C ??? 0 votes 0 votes A_i_$_h commented Jul 19, 2017 reply Follow Share a small mistake in the question, i have edited it now 0 votes 0 votes joshi_nitish commented Jul 19, 2017 reply Follow Share then answer will be '1'... 0 votes 0 votes Please log in or register to add a comment.
Best answer 0 votes 0 votes wow,,,, it is a tricky question A B' C' + D' C + [ ( A' + B + C)(D + C')] let x = A B' C' + D' C then x'= (A'+B+C)(D+C') ie here we got x + x' which is equal to 1(as we know x+x'=1) pawan kumarln answered Jul 19, 2017 • selected Jul 19, 2017 by A_i_$_h pawan kumarln comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes [ ( A' + B + C)(D + C')] = (A B' C' + D' C)' ( By deMorgan's identity of (X+Y)'=X'Y') A B' C' + D' C + [ ( A' + B + C)(D + C')] =A B' C' + D' C +(A B' C' + D' C)' hence A B' C' + D' C +(A B' C' + D' C)'=1 as x+x'=1 hence it is simplified to 1 Neeraj Chandrakar answered Jul 23, 2017 Neeraj Chandrakar comment Share Follow See all 0 reply Please log in or register to add a comment.