2 votes 2 votes https://gateoverflow.in/?qa=blob&qa_blobid=6062310458167884954 Kanchan kumari asked Jul 19, 2017 Kanchan kumari 315 views answer comment Share Follow See 1 comment See all 1 1 comment reply rahul sharma 5 commented Jul 19, 2017 reply Follow Share Would you mind attaching image properly? 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes Ans .C R1(ABC) AB->C R2(CD). C->AD C is key of R2, but C->A violates BCNF condition in R1 as C is not a key. We cannot decompose ABC further as AB->C dependency would be lost. Hence,it is ANSWER. Raushank2 answered Jul 19, 2017 Raushank2 comment Share Follow See all 0 reply Please log in or register to add a comment.
