Testing as per Option,Assume Transmission time =t
Option a)Optimum size= 4Bytes.i.e
Total packets required are 6 packets each of size 4Bytes which makes Msg size=24B
1)for 1st packet: Time required= 3* transmission time=3t (assume tp=0)
2)1)for remaining 5 packets: Time required= 5* transmission time=5t {due to paralellism}
Total time =3t+5t=8t
Option b)Optimum size= 6Bytes.i.e
Total packets required are 4 packets each of size 6Bytes which makes Msg size=24B
1)for 1st packet: Time required= 3* transmission time=3t (assume tp=0)
2)1)for remaining 3 packets: Time required= 3* transmission time=3t {due to paralellism}
Total time =3t+3t=6t
Option c)Optimum size= 7Bytes.i.e
Total packets required are 4 packets each of size 7Bytes which will envelope msg into packet by keeping some free space .i.e Msg size=24B
1)for 1st packet: Time required= 3* transmission time=3t (assume tp=0)
2)1)for remaining 3 packets: Time required= 3* transmission time=3t {due to paralellism}
Total time =3t+3t=6t
Option d)Optimum size= 9Bytes.i.e
Total packets required are 3 packets each of size 9Bytes which will envelope msg into packet by keeping some free spacei.e Msg size=24B
1)for 1st packet: Time required= 3* transmission time=3t (assume tp=0)
2)1)for remaining 2 packets: Time required= 2* transmission time=2t {due to paralellism}
Total time =3t+2t=5t