doubt

Question

#include<stdio.h>
int main()
{
    char c = 125;
    c = c+10;
    printf("%d", c);
    return 0;
}

in this we know -121 is printed also know the logic

but what will be in

int main()
{
    char c = 125;
    c = c+10;
    printf("%u", c);
    return 0;
}

plz explain with logic

Answer 1

char c=125=01111101

c=c+10=01111101+1010

c=10000111

now value of 'c' will be printed uaing %u specifier, but %u specifier wants the provided input to be of size of int..

therfore we will promote the value of 'c' to 4 bytes using 2's complement sign bit extension technique..

value after performing sign bit extension(4 bytes) c=11111.....10000111, now its unsigned value is 4294967175 which will get printed

Comments

got it,,,also here perfect expalination by @arjun sir

https://gateoverflow.in/139773/data-type?show=139889#c139889