This is a correct solution to the critical section problem.
Reason:-
satisfies mutual exclusion :-value of turn can be either i or j at the same time so any one process can be in cs.
satisfies progress-after execution of each process its flag is set to false (see in the exit section) .as this flag goes to f other waiting process whose flag value is 1(process interested to enter cs) will enter the cs as while loop condition satisfies in this sitiuation.
bounded waiting-after completing its execuion in cs its flag is set to false which allow other process to enter the cs .the same process cant be executed again and again indefinetly if other process is ready and waiting.