william stallings 8th ediiton

Question

Answer 1

4

6

6

total no. of 2 operand = 2⁴  

k  2 operand are given so total no. of 1 operand = 2⁴ -k

let x be the one operand and zero operand given L

so L = ((2⁴ -k)*2⁶ - x)*2⁶

by solving we get one operand (x) = ((2⁴-k)*2¹²-L)/2⁶