How does the function return in the below code ?

Question

#include <stdio.h>
void e(int);
int main()
{
int a = 3;
e(a);
putchar('\n');
return 0; }
void e(int n)
{
if (n > 0)
{
e(--n);
printf("%d ", n);
e(--n);
}
}

I am not getting here that when e(0) is called how is the code executed ?

Answer 1

when e(0) is called, if condition becomes false, and control doesn't go into if block, and simply returned from e() function.

Comments

So after returning at which statement would it come ?

---

It will come at statement just after the call to e(0).