2 votes 2 votes 10 distinct accident occurs in a week.What is the probability that all accidents occured on the same day ? gaurav456 asked Aug 2, 2017 gaurav456 473 views answer comment Share Follow See 1 comment See all 1 1 comment reply sachin! commented Dec 17, 2017 reply Follow Share This is discrete random variable Given mean 10 accident in a week so on avg no of accident in a day 1/10 So finding probability of 10 accident in a day =(e^(-1/10)×(1/10)^10)/10! 0 votes 0 votes Please log in or register to add a comment.
1 votes 1 votes The probability that all accidents occurred on the same day: 1/(7^9). there are: 7^10 total outcomes. and favourable one`s are 7 (all on same day.). saxena0612 answered Aug 2, 2017 saxena0612 comment Share Follow See all 2 Comments See all 2 2 Comments reply vikash tyagi commented Dec 17, 2017 reply Follow Share HOW TOTAL FAVORABLE OUTCOMES ARE 7 RAISED TO POWER 10 0 votes 0 votes hs_yadav commented Dec 17, 2017 reply Follow Share 10 Accident.... every accident may occure any one of 7 days....and are independent to each other...therefor all possibilities are 710 ... The probability that all accidents occurred on the same day: 1/(7^9). Explaination:- probability of first acciden to accure at any day is 100%(given) ..... now after first exident probability of 9 accident occure on same day is...(1/7)^9 ...total probability is ....1/7^9 *1 0 votes 0 votes Please log in or register to add a comment.