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Average access time

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Consider two level memory systems in which the average access time is 150 ns without level L1 . The level 1 access time is 20 ns . The average access time with L1 is 40 ns. The hit ration of L1 in percengage........

Plz help me to find the correct answer.. I got 88%
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Average access time is 150 ns without level L1, it means L2 access time is 150 ns, because if L1 is not present all memory references will be accessed from L2.

L1 A.T = 20 ns
L2 A.T = 150 ns

Average A.T with L1 = Hit in L1*(L1 A.T) + MissinL1( L1 + L2 A.T)
                               40ns = h1*20ns + (1-h1)*170ns
                                40ns = 20h1 -170h1 + 170ns
                                 150h1 = 130
                                   h1=0.8666 or 86.67%
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