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Let the number of bits required to address a memory word be 25.  Each word is of 16 bits.

  1. Number of words in the memory is ________.

  2. Number of bytes in the memory denoted as ____________

  3. Number of bits to address __________.

Where W denotes word and B denotes bytes.

1 Answer

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Number of words = Total number of unique memory address = 2$^{25}$

Number of bytes in memory = total number of words * size of each word = 2$^{25}$* 2 Bytes= 2$^{26}$ Bytes of 64 MB

Number of bits to address a particular word is = 25 bits as 2$^{25}$ unique block are possible

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