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5 Answers

1 votes
1 votes
It is 0^0 formate apply L hospital

= e ^ limt x-> 0 (sinx ln x)

e^ limt x->0 (lnx/cosecx) apply L hospital

e ^ limt x->0 (-(sinx/x cotx))

e ^ 0

=1
0 votes
0 votes
1 fx power gx type function
0 votes
0 votes
This problem is in 0^0 form so, we cant apply L Hopital Rule .

Please follow the below step and you will get the answer.

Take Log on both the side and bring the limit in O/O form .

Apply L Hopital and solve further.

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