2's compliment

Question

The Decimal equivalent of 2’s complement representation of 8 bit integer is most positive when
except _________
(A) MSB are zeros

(B) LSB are zeros
(C) MSB are ones

(D) LSB are ones

Comments

C in big endian?

Answer 1

Range of n-bit 2's complement representation is -2^(n-1) to +{2^(n-1) -1}

For n=8, maximum positive value is 2^(8-1) -1 which is 127

Now, in 8 bits, 127 = (01111111)₂ {$\because$ non-negative numbers are represented by their n-bit binary equivalents}

So, except MSB all are 1's. The options are not correctly given. It should be except MSB all are ones.