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Taking A=0, LHS= B'+C'

and RHS= B'C'

Taking A=1 ,LHS=BC

RHS= BC

Now for A=1 it is satisfied while for A=0 not satisfied so does the identity hole or not ?

1 Answer

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method (1)

LHS=A x-nor (BC)=ABC+(A)'(BC)'=ABC+(A)'(B'+C')=ABC+A'B'+A'C'

RHS=(AB+A'B')(AC+A'C')=ABC+A'B'C' 

SO, LHS!=RHS

method(2)

A B C Ax-nor(BC) (A xnor B)(A xnor C)
0 0 0 1 1
0 0 1 1 0
0 1 0 1 0
0 1 1 0 0
1 0 0 0 0
1 0 1 0 0
1 1 0 0 0
1 1 1 1 1

so from this truth table also LHS != RHS

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