@manu00x or @joshi_nitish.

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+1 vote

Flag 0111 means in data part you have to stuff a 0 after every occurence of 11. So given data part is 011111 So after bit stuffing it will be 01101101

If flag contain consecutively n one then in data part you havr to stuff a 0 after every (n-1) one

0

flag 0111 means that we must stuff bit after every occurrence of 011 not 11. In forouzan it is mentioned as "In bit stuffing, if a 0 and five consecutive 1 bits are encountered, an extra 0 is

added for flag 01111110."

added for flag 01111110."

0

+2

i have also read in frouzan that we have to stuff 0 after occurence of 011.. but in other books like tennebaum and lectures of neptel i have found that they used the method of stuffing after occurence of 11... its really confusing which way to opt.

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Actually I asked this question for altogether different reason. If we stuff 0 after every 011 (flag is 0111) then the data will be 011* 0*111 . Here after stuffing 0, at the end we have 0111 which is same as flag and the problem is not solved.

0

Well your answer lies in our discussion.. Because if you go through the approach that 0 will be added after every 11 then there will be no problem isn't??

0

+1

http://web.mit.edu/modiano/www/6.263/lec2.pdf

I have seen previous year gate paper in that they use to stuff 0 bit after every n-1 occurrences of 1.

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