@joshi_nitish @just_bhavana

Check it once!

The Gateway to Computer Science Excellence

+1 vote

Q. Compute the approximate optimal window size when packet size 53 byte and round trip time (RTT) is 60 ms and bandwidth (BW)155 mbps (in byte) using sliding window protocol.

0

For optimal window size exhaust your bandwidth in given RTT so sender in never idle (Thats the basic idea).

so bandwidth = 155Mbps

and RTT = 60 ms

so in 1 sec we may send 155MB

in RTT it should be 155 MB * 60 ms = 9300 KB

packet size is 53 B

win size = 9300 KB / 53 B

=175.47169 K or 175471 (taking floor as what we have just calculated is the maximum limit so cant go further).

so bandwidth = 155Mbps

and RTT = 60 ms

so in 1 sec we may send 155MB

in RTT it should be 155 MB * 60 ms = 9300 KB

packet size is 53 B

win size = 9300 KB / 53 B

=175.47169 K or 175471 (taking floor as what we have just calculated is the maximum limit so cant go further).

- All categories
- General Aptitude 1.9k
- Engineering Mathematics 7.6k
- Digital Logic 2.9k
- Programming and DS 4.9k
- Algorithms 4.4k
- Theory of Computation 6.2k
- Compiler Design 2.1k
- Databases 4.1k
- CO and Architecture 3.4k
- Computer Networks 4.2k
- Non GATE 1.4k
- Others 1.5k
- Admissions 595
- Exam Queries 573
- Tier 1 Placement Questions 23
- Job Queries 72
- Projects 18

50,833 questions

57,742 answers

199,469 comments

108,050 users