retagged by
331 views
1 votes
1 votes

The relation R (ABCDE) with FD set $\{AB \rightarrow CDE, \ A \rightarrow C, \ C \rightarrow D\}$ is in which of the following normal forms?

  1.  1NF but not in 2NF
  2.   in both 2NF and 3NF
  3.   in 3NF but not in BCNF
  4.   in BCNF
retagged by

2 Answers

Best answer
2 votes
2 votes

First, we need to find the candidate keys.

From the given functional dependencies, only $AB$ is the candidate key.

We have a partial dependency here,

$A \rightarrow C$

So, it is not in $2NF$.

Hence, option (A) 1NF but not in 2NF

selected by
1 votes
1 votes
C is not fully functionally dependent on candidate key AB because A-->C. so it is not in 2NF.So answer is A
Answer:

Related questions

3 votes
3 votes
1 answer
2
3 votes
3 votes
1 answer
3
Bikram asked Aug 26, 2017
678 views
Decompose the following table into BCNF:$R(ABCD)$$A \rightarrow C$$C \rightarrow A$$AB \rightarrow D$The result is:(AC) (ABD)(AC) (CBD)(AB)(BAD)Both (A) & (B)