Query 1 first we do the cross product of both table
return tuple in which dno (of student table ) =dno (dno of department )
during the cross product two different dno attribute will be created one from the student table and one from the dept table
eno, ename , s.dno, d.dno,dname
Query 2 natural join takes place on the common attribute
so only those tuple will be created in which dno (of student table ) =dno (dno of department )
and the result table contain only one dno
eno, ename , dno, dname
so the option d is answer