611 views
1 votes
1 votes
Johnny has bought two candles of equal length but different diameters. One of the candles will burn up completely in 10 hours, while the other candle requires 40% more time to burn up completely. If the candles are lit at the same time, approximately how long will they burn before one of the candles is twice the length of the other?

1)7.8 hours

2)6.4 hours

3)5.6 hours

4)6 hours

1 Answer

1 votes
1 votes
suppose both candle of length x meter.

1 candle burning  x/10 meter per hour

2nd candle burn completely in 10*140/100=14 hour

so ,2nd candle burning x/14 meter/hour

let after y hour 1 st candle length is half of 2 nd candle as 1st candle burn faster

so , length of 1st candle after y hour=x-x/10*y

length of 2nd candle after y hour=x-x/14*y

so length of 1st candle should be half of 2nd candle

x-xy/10=1/2(x-xy/14)

x-xy/10=x/2-xy/28

x/2=18xy/280

y=280/36 = 7.777 hour  ~ 7.8 hour

Related questions

0 votes
0 votes
0 answers
1
0 votes
0 votes
0 answers
2
radha gogia asked Nov 16, 2018
506 views
Answer given is Option A , but here we wil first sort the jobs in order of profit , for each value of deadline scan linearly in the array depending on the value of deadli...
0 votes
0 votes
0 answers
3
Sheikh Rafi asked Feb 24
74 views
A program is running on a specific machine (CPU) with the following parameters:i) Total instructions executed =10^7ii) Average CPI = 2.5 cycles per instruction.iii)CPU cl...