Number system made easy

Question

How many 1s in Binary represention of (1*4096)+(9*256)+(7*16)+5??

 

And

 

2s compliment of -17??

Comments

Last term is missing in ur first part of the question..

---

Sorry

Answer 1

each power of 2 will contain single 1.
=2^12 + ((1 +8)2^8) + (( 1 + 2 + 4)2^4) + 4 +1
=2^12 + 2^8 + 2^11 + 2^4 + 2^5 + 2^6 + 2^2 + 2^0
there will be 8 1's.

2's complement of -17

17 = 0001 0001, (take 2's complement)

-17 = 11101111

Comments

and if it is asked to write in BCD, 2's comp of -17 then

---

@ manu, your answer makes sense ,but i want to ask 1 thing that why you represented $-17$ using $8$ bits,

i could have represented $-17$ using $6$bit (minimum)

$(-17)_{10}=(110001)_{2}$

$2^{s}$ complement=$(101111)_{2}$

making answer $6$