As we can see the precedence graph is creating a cycle. $\implies$ It is not a conflict serializable schedule
Also there is no blind write in the given schedule $\implies$ It is not view serializable (As it is not a conflict serializable schedule. ) $\implies$ It is not serilizable schedule.
Also if a schedule is not serializable then it cannot be 2PL $\implies$ It is not 2PL schedule.
$\therefore$ Option $D.$ is correct answer.