DUAL: if you change
(1) OR <-----> AND
(2) 0<-------->1
Demorgan's law :
(1)OR <-----> AND
(2) 0<-------->1
(3) literal's is complimented
ie dual property is subset of Demorgan's property.
example
let expn is v + ∼u (x+y∼z)
(∼ means NOT operator)
dual : v.(∼u+(x.(y+∼z)))
for Demorgan's just the compliment the literals of DUAL expn
Demorgan's : ∼v.(u+(∼x.(∼y+z)))