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Please solve the b and c parts:

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Option B.
$L1^{3}$ = L1 . L1 . L1   (Concatenation of L1 3 times).

You have already found the Grammar of L1.

X $\rightarrow$ SSS

Now X will be the start symbol.

Option C.
L1* = $L1^{0}$ $\cup$ $L1^{1}$ $\cup$ $L1^{2}$ $\cup$ ....... So on.

Add this line in the production of L1.

Y $\rightarrow$ SY / $\epsilon$

Now Y will be Start symbol.
by Boss (16.1k points)
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