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6's complement of $(268)_{10}$

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6's complement of N = [268]10   is

(a) 4432        (b) 4342      (c) 3432       (d) None

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$\left ( 268 \right )_{10}=\left ( 1124 \right )_{6}$

$5^{s}$ complement of $\left ( 1124 \right )_{6}$=$\left ( 5555-1124 \right )_{6}=\left ( 4431 \right )_{6}$

$\Rightarrow 6^{s}$ complement =$\left ( 4431 +1\right )_{6}$=$\left ( 4432 \right )_{6}$
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