retagged by
3,927 views
8 votes
8 votes

16 bit Floating Point Representation

$(-1)^{sign}*(1.M)*2^{Exp - 63}$

Sign = 1 bit Exponent = 7 bit Mantissa = 8 bit

1) Max positive number

2) Min positive number.

3) Max negative number.

4) Min negative number.

5) What is meant by precision.

retagged by

2 Answers

0 votes
0 votes
Following IEEE standard exponent all 7 bit 1 that is 127 is reserved for special purpose

Thus max possible +ve value is +1.11111111*$2^{126-63}$

Min Possible -ve Number is -1.11111111*$2^{126-63}$

Min possible +ve value is (demoralized form)  +0.00000001*$2^{-62}$

MAX possible -ve value is -0.00000001*$2^{-62}$
edited by

Related questions

5 votes
5 votes
2 answers
1
gate_forum asked Oct 14, 2015
1,269 views
32 bit floating point representation of decimal number 3.284*10^4 is(A) 010001101111110111000000000000(B) 110001101111110111000000000000(C) 011010101111110111000000..(D) ...
1 votes
1 votes
1 answer
3
Aboveallplayer asked Jan 18, 2017
1,787 views
what is the hexadecimal representation of the floating point number (-48.625) in single precision, after rounding off and normalisation
4 votes
4 votes
2 answers
4