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S1 : All the elements in A are mapped to  B , therefore f is a valid function (S1 is true)

S2 : All the elements in B are not mapped to  C, therefore g is not a valid function (S2 is false)

S3 : f(g(1)) cant be found because g(1) has no mapping therefore f 0 g is not valid ( S3 is false)

S4: g(f(1)) = g(2) = 0 (since f(1) =2 g(f(1)) becomes g(2) )

      g(f(2)) = g(3) = 1

      g(f(3))=g(4) =1

A mapping is obtained for all elements , therefore g o f is valid (S4 is true)

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