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Programming

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2 votes
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Please explain the output.

#include<stdio.h>

int main()

{

  int c;

  printf("geeks for %ngeeks ", &c);

  printf("%d", c);

  getchar();

  return 0;

}

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1 Answer

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Output would be "geeks for" followed by some garbage value...%n in printf statement specifies print all the charcters before the occurence of %n
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