2 votes 2 votes If x=1 in the logic equation [X+Z{Y'+(Z'+XY)}]{X'+Z'(X+Y)}=1 THEN a) Y=Z b) Y=Z' c) Z=0 d) Z=1 Sunidhi chauhan asked Sep 23, 2017 Sunidhi chauhan 8.2k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 5 votes 5 votes [X+Z{Y'+(Z'+XY)}]{X'+Z'(X+Y)} = 1 [1+Z{Y'+(Z'+XY)}]{X'+Z'(X+Y)} = 1 since 1 + x = 1 1.{X'+Z'(X+Y)} = 1 since 1.x = x {0+Z'(X+Y)} = 1 X = 1 implies X' = 0 and 0 + x = x {Z'(1+Y)} = 1 {Z'.1} = 1 Z' = 1 Z = 0 option C Shivam Chauhan answered Sep 23, 2017 selected Sep 29, 2017 by mcjoshi Shivam Chauhan comment Share Follow See all 0 reply Please log in or register to add a comment.