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If x=1 in the logic equation

[X+Z{Y'+(Z'+XY)}]{X'+Z'(X+Y)}=1 THEN

a) Y=Z  

b) Y=Z'

c) Z=0

d) Z=1

1 Answer

Best answer
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5 votes

[X+Z{Y'+(Z'+XY)}]{X'+Z'(X+Y)} = 1

[1+Z{Y'+(Z'+XY)}]{X'+Z'(X+Y)} = 1  since 1 + x = 1

1.{X'+Z'(X+Y)} = 1  since 1.x = x

{0+Z'(X+Y)} = 1   X = 1 implies X' = 0       and   0 + x = x

{Z'(1+Y)} = 1

{Z'.1} = 1

Z' = 1

Z = 0

option C

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