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Find the value of P

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Consider the following code

What is the output printed by the above code in terms of n?

How it is coming b??

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It is given i < 2n  not i<=2n  Thus the answer is $\frac{3n^{2}-3n}{2}$

If i<=2n then $\frac{3n^{2}-n}{2}$

for i<=n+1 sum is 1+2+3+...+n = $\frac{n^{2}+n}{2}$

for n+1< i < 2n  sum is n(n-2) = $n^{2}-2n$

total sum  = $\frac{3n^{2}-3n}{2}$

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