UGC NET CSE | December 2008 | Part 2 | Question: 26

Question

The output of the program code

main()
{
int x=0;
while (x<=10)
for(;;)
if(++x%10==0)
break;
printf(“x=%d”,x);
}

is :

• A. x=1                
• B. compilation error
• C. x=20                       
• D. none of the above

Comments

(C) x=20

---

How the value is 20

Answer 1

The Answer is C). X=20

When While loop enters for the first time, x=0. So, It enters the loop. Then there is infinite for loop where it breaks when x becomes multiples of 10.

When ++x becomes 10, then 10%10==0 → True, so, it breaks the for loop

After that, It goes again into while loop, where it checks condition for x<=10 and it gets satisfied as x=10 now. So, The For loop again iterates for 10 times till x becomes 20. When X=20, It breaks the for loop. Now, The while condition is checked x>10. Condition fails.

Finally, It prints X=20

Answer 2

(D) none of the above

it will be print 9