Pointers

Question

int main()

{

static int a[]={0,1,2,3,4};

static int *p[]={a,a+1,a+2,a+3,a+4};

printf("%u%u%d",p,*p,*(*p));

}

Answer 1

let us assume integer is of 2 bytes and pointer is of 4 bytes........i am considering some addresses of arrays./

Comments

I have a doubt

int p,i=0;

p=&i;

printf("%d",p) ; will print address of variable i

So in the above code

static int *p[]={a,a+1,a+2,a+3,a+4};

printf("%d",p); is printing base address of p array why it is not printing address of array it is pointing

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here p is not pointing to a single variable, it acts as an array of pointers and as the mnemonic(or name) of an array represents its base address, p would give us base address of that array of pointers...

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P is an array pointer which contains the addresses of array A.....and this array p has a base address....so print(p) means print base address of p.....not only in this case but in another cases also if an array A is given and we write print(A) it should print base address of A not the addresses the array A is pointing to.