0 votes 0 votes Amit puri asked Sep 28, 2017 Amit puri 321 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply stblue commented Sep 28, 2017 reply Follow Share 1101000111 is it correct ?? 0 votes 0 votes Ashwani Kumar 2 commented Sep 28, 2017 reply Follow Share 1101000111 is correct but by default assuming it as up counter? 0 votes 0 votes stblue commented Sep 28, 2017 reply Follow Share @Ashwani Kumar 2, answer given by aakshat is correct, we can't decide its up or down counter..even this concept was new to me. @amit puri thanks for asking this question. Here read about it https://en.wikipedia.org/wiki/Ring_counter 0 votes 0 votes Ashwani Kumar 2 commented Sep 28, 2017 reply Follow Share @stblue Yeah correct.... Yes it is well known that Johnson counter performs grey coding. You can also see this gate question for a better idea https://gateoverflow.in/8219/gate2015-1_20 1 votes 1 votes Please log in or register to add a comment.
Best answer 4 votes 4 votes Ans ->1011010001 twisted ring counter is mod2n so at 20 clock cycle it will be at initial position so at 2 clock cycle (~q0 shift to right) from 1 cycle akshat sharma answered Sep 28, 2017 • selected Sep 28, 2017 by Amit puri akshat sharma comment Share Follow See all 0 reply Please log in or register to add a comment.