TOC: Complement of the given language closed

Question

Is the following language CFL?

L = complement of {$a^ib^jc^k$ | i!=j and j!=k}

Comments

not a cfl.

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i think L = ($\sum$* - a*b*c*) $\cup$ ({aⁱb^jc^k| i=j or j=k})

which is CFL

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@nitish I too think the same, that it is CFL but in Gateforum it is given not CFL, hence i asked.

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@manu00x

please, see my answer again

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@nitish, i think your logic is absolutely correct, this language mentioned by you will exlcude only the language when a,b,and c are not equal.

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If the question were 

L = complement of {aⁱb^jc^k | i!=j OR j!=k}

This would not be a CFL but just a CSL right?