17 votes 17 votes What will be the maximum sum of $44, 42, 40, \dots$ ? $502$ $504$ $506$ $500$ Quantitative Aptitude gatecse-2013 quantitative-aptitude easy arithmetic-series + – Arjun asked Sep 24, 2014 edited Jun 8, 2018 by Milicevic3306 Arjun 5.6k views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply KULDEEP SINGH 2 commented Jan 24, 2017 reply Follow Share For maximum sum we have to go from 44 to 0 i.e total 22 element apply formula sum of 'n' even number = n(n+1) = 22*23 = 506 4 votes 4 votes Chhotu commented Oct 17, 2017 reply Follow Share Simply use (n/2)(a+d) Here a =0, d = 2 and n = 23. 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes = 2 ( 22 + 21 +20+19.................0) = 2 ( 22 (22+1)/2 ) =506 option c air1ankit answered Nov 29, 2018 air1ankit comment Share Follow See 1 comment See all 1 1 comment reply Bharti goyal commented Dec 4, 2018 reply Follow Share 2+4+6+......44 N=22 d=2 a=2 Sum=N/2{2a+(N-1)d} Sum=22/2{4+(21)2} Sum=11{4+42} Sum=11*46 Sum=506 0 votes 0 votes Please log in or register to add a comment.