Programming

Question

#include<stdio.h>

int main()

{ Float x=0.5;

if(x==0.5)

Printf("if");

else if(x==0.5f)

Printf("else if");

}

Explain the code line by line .

Comments

It's compiler dependent.

#include<stdio.h>

int main()

{
    float x=0.55;
    if(x==0.55)
        printf("if");
    else if(x==0.55f)
        printf("else if");
    return 0;
}

This will print "else if"

---

https://stackoverflow.com/questions/3954498/how-to-convert-float-number-to-binary

From here you can get the actual thing.

---

@Tushin Dutta

.55 is actually not getting properly converted to binary number that's why it will always print "else if".

You can check from the link below whether a floating number will be converted into binary or not.

https://stackoverflow.com/questions/3954498/how-to-convert-float-number-to-binary

Answer 1

The answer should be else if becAuse decimal numbers are by default double so 0.5 is considered as double well the initialization should be as float x = 0.5f though, But it won't give any error but comparison of x with 0.5 will return false and else if will be printed.

yea its true as its compiler dependent.