3 votes 3 votes Minimum size of ROM required to implement following set of Boolean equations is F1 (w,x,y,z) = Σm( 0,1,2,5,7,12,13,15 ) F2 (w,x,y,z) = Σm( 0,5,6,9, 13,15 ) F3 (w,x,y,z) = Σm( 6,7,9,12,14,15 ) (a) 16 x 4 (b) 16 x 3 (c) 16 x 8 (d) 16 x 12 Digital Logic digital-logic k-map + – Harsh Mehta asked Oct 5, 2017 Harsh Mehta 2.0k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 3 votes 3 votes We have four variable functions. Thus number of minterms = 16 Decoder size 4 * 16 and we need to implement three functions thus three lines needed. ROM size 16 x 3 Shivam Chauhan answered Oct 6, 2017 • selected Dec 7, 2017 by Shivam Chauhan Shivam Chauhan comment Share Follow See all 0 reply Please log in or register to add a comment.