# BINOMIAL DISTRIBUTION

629 views
Consider an unbiased cubic dice with opposite faces coloured identically and each face coloured red, blue or green such that each colour appears only two times on the dice. If the dice is thrown thrice, the probability of obtaining red colour on top face of the dice at least twice is----

I am getting 0.75 can anyone confirm this ?
0
$\binom{3}{2}*(\frac{1}{3})^{2}* \frac{2}{3} + \binom{3}{3}*(\frac{1}{3})^{3} = \frac{7}{27} = 0.259$
0
Why can't we do like P[x>=2]=1-{P[x=0]+P[x=1]}  ?

0.2592

Unbiased cubic dice with opposite faces coloured identically and each face coloured red, blue or green such that each colour appears only two times on the dice means $\frac{2}{6} = \frac{1}{3}$ is probability of each color comes on top.

For 2= $\binom{3}{2}(\frac{1}{3})^{2} \frac{2}{3}$ = $\frac{4}{9}$

For 3= $\binom{3}{3}(\frac{1}{3})^{3}$ = $\frac{1}{27}$

Total = $\frac{7}{27}= 0.252$

selected
0

@ Prashant.  Why can't we do like P[x>=2]=1-{P[x=0]+P[x=1]}  ?

1
You can do it . answer is same . 1- 20/27

## Related questions

1
869 views
Probability of getting a total of 7 atleast once in three toss of a fair die is 125/216 91/216 117/216 9/216