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How to check?

Write T1 -> T2. T2-> T1.

See that none of the operations can be moved up or down
as w1(z) and r2(z) conflicts in 1st and w2(x) r1(x) conflicts in 2nd.

So none of the non serial schedule can be conflict serializable hence not 2PL.

We can have circular wait in some of the non serial ordering.

So D is correct.

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sivajagsa asked Jan 29, 2017
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S: R1(A), R3(D), W1(B), R2(B), R4(B), W2(C), R5(C), W4(E), R5(E), W5(B)Number of serial schedules which are view equal to above S are __.Polygraph that I drew: