1 votes 1 votes 1 0 [3x] dx Surya Dhanraj asked Oct 9, 2017 Surya Dhanraj 491 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
2 votes 2 votes first draw function y=[3x] it will y=0 when x=[0 ,1/3) y=1 when x=[1/3,2/3) y=2 when x=[2/3,1) y=3 when x= [3,4/3) we need to find algebric area till x=1 so area =0*(1/3)+1*(2/3-1/3)+2*(1-2/3) =0+1/3+2/3=1 sachin! answered Oct 9, 2017 sachin! comment Share Follow See all 2 Comments See all 2 2 Comments reply Surya Dhanraj commented Oct 9, 2017 reply Follow Share Can u please draw the graph also... 0 votes 0 votes Surya Dhanraj commented Oct 9, 2017 reply Follow Share How to find point of discontinuity in [3x].. 0 votes 0 votes Please log in or register to add a comment.