dynamic scoping

Question

int i=10;
main()
{
int i =5,k,i=6;
printf("enter value");
scanf("%d",&k);
if(k>0)
{
fun1();
}
else
{
fun2();
}
}

void fun1();
{
printf("%d",i);
}

void fun2();
{

int i=5;
printf("%d",i);
fun1();

}

what will the output using dynamic scoping?

Answer 1

by taking any value of k   (k>0 )

OUTPUT will be 6

 and if we take k=0

then , OUTPUT will be 5 5

Answer 2

Case 1:Suppose K is 10 then f1 calls

It will print 10 because value is not passed

Case 2:suppose K is -2

Then f2 calls in this case

5 10 prints as output