0 votes 0 votes A node $X$ on a $10$ Mbps network is regulated by a token bucket. The token bucket is filled at a rate of $2$ Mbps. Token bucket is initially filled with $16$ megabits. The maximum duration taken by $X$ to transmit at full rate of $10$ Mbps is ______secs. $1$ $2$ $3$ $4$ Computer Networks ugcnetcse-jan2017-paper3 computer-networks token-bucket + – go_editor asked Mar 24, 2020 • recategorized May 24, 2020 go_editor 2.0k views answer comment Share Follow See all 5 Comments See all 5 5 Comments reply Show 2 previous comments papesh commented Jan 25, 2017 reply Follow Share Sir it's 16Mbits / (10Mbps - 2Mbps )= 2sec 2 votes 2 votes Sanjay Sharma commented Feb 2, 2017 reply Follow Share https://gateoverflow.in/111026/net-jan-17-paper-3-q30-token-bucket 1 votes 1 votes sachin! commented Oct 10, 2017 reply Follow Share 16+2*x=10*x x=2 sec 1 votes 1 votes Please log in or register to add a comment.
4 votes 4 votes Maximum burst time = Capacity /(Output rate-Arrival rate ) = 16/(10-2) = 2 seconds sh!va answered Jan 31, 2017 sh!va comment Share Follow See all 0 reply Please log in or register to add a comment.
3 votes 3 votes Using $T=\frac{C}{R_{out}-R_{in}}$ ans comes out to be 2 sec(where C=16Mbits $R_{out}$=10Mbps and $R_{in}$=2Mbps)......:-) Anmol Verma answered Jan 27, 2017 Anmol Verma comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes In token bucket algo $C+\rho * S = M * S \\ C= Capacity \ of \ bucket \\ \rho = Token \ arrival \ rate \\ M = Maximum \ Output \ rate \\ S = Burst \ Time$ S = (16-2)/8 = 2 sec Hence option 2) is correct Ashwani Kumar 2 answered Oct 11, 2017 Ashwani Kumar 2 comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes 2) 2 s Neeraj Chandrakar answered Oct 15, 2017 Neeraj Chandrakar comment Share Follow See all 0 reply Please log in or register to add a comment.