2 votes 2 votes [ D110 ; / ] = { 1,2,5,10,11,22,55,110} how are these values identified A_i_$_h asked Oct 11, 2017 A_i_$_h 465 views answer comment Share Follow See 1 comment See all 1 1 comment reply LeenSharma commented Oct 11, 2017 reply Follow Share all are the divisor of 110. 0 votes 0 votes Please log in or register to add a comment.
Best answer 2 votes 2 votes [Dn;/] is poset which is also a distributive lattice and it contains all divisors n. Here n = 110 which can be written as 21 x 51 x 111 = (1+1) * (1+1) * (1+1) = 8 = number of divisors of 110 {1,2,5,10,11,22,55,110} these all are divisors of 110 [D110 ; /] is also a boolean algebra. Shivam Chauhan answered Oct 11, 2017 • selected Oct 11, 2017 by srestha Shivam Chauhan comment Share Follow See all 2 Comments See all 2 2 Comments reply A_i_$_h commented Oct 11, 2017 reply Follow Share but how do u find these 8 divisors 0 votes 0 votes Shivam Chauhan commented Oct 11, 2017 reply Follow Share prime factorization of 110 = 2 x 5 x 11 = calculate their combinations $\binom{3}{1}$ [divisors are 2,5,11] + $\binom{3}{2}$ [divisors are 2x5 , 5x11 , 11x2] + [1,110] = 8 divisors 1 votes 1 votes Please log in or register to add a comment.