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+1 vote
66 views
i=0;

j=--i ;

printf( i++  +  --i  +  i--  +  j-- + --i + i);

the output??
asked in Programming by Junior (809 points) | 66 views

1 Answer

0 votes
It is compiler dependent output.

Is based in the concept of sequence points.
answered by Active (3.6k points)


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