1 votes 1 votes i=0; j=--i ; printf( i++ + --i + i-- + j-- + --i + i); the output?? Programming in C programming-in-c + – aaru14 asked Oct 11, 2017 aaru14 247 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes It is compiler dependent output. Is based in the concept of sequence points. Angkit answered Oct 11, 2017 Angkit comment Share Follow See all 0 reply Please log in or register to add a comment.