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3 boys and 4 girls have to sit in a row with all arrangements equally likely. What is the probability that no 2 boys sit next to each other

a)1/7  b)2/7  c) 3/7  d)4/7
asked in Combinatory by Boss (48.6k points) | 78 views
+1

Total cases of filling 7 seats = 7! 

Now Place 4 girls first = 4! ways _ G1_G2_G3_G4_

Now we have 5 position  and 3 boys = 5p

So probability = (5p ) 4!  / 7! = 2/7

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