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+1 vote
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I am getting answer as 88.6 time unit. 

using Total page service time = 250 x 0.94 + 0.06 x 450 = 262 time units

Access time = p( page service time + m) + (1-p)(m)  = p * page service time + m   ( p is page fault rate) 

Substituting the values i got access time = 88.6 time unit. 

but the answer is 85.6 time unit. Please point where i am going wrong. 

asked in Operating System by (289 points) 1 5 | 35 views
mine coming 93.1

dirty page should also considered
I think dirty page is considered in Total page falult time that i have calculated, Isn't it,

could you please explain how did you get 93.1 Please.

1 Answer

0 votes
The average access time

(1-p)memory access time+p(memory access time+page fault service time +dirty page service time)

=0.7(10)+0.3(10+250+0.06*450)

=7+0.3(260+27)

=7+0.3*287

=93.1 time units
answered by Veteran (65.1k points) 35 222 625

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