1 votes 1 votes What would be the bias value for a. A base-2 exponent in a 6-bit field? b. A base-8 exponent in a 7-bit field? arch asked Oct 12, 2017 arch 547 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 1 votes 1 votes The base is irrelavent bias= (2^(6-1))-1=(2^5)-1=32-1=31 bias= (2^(7-1))-1=(2^6)-1=64-1=63 Deepthi_ts answered Oct 12, 2017 selected Oct 12, 2017 by srestha Deepthi_ts comment Share Follow See all 2 Comments See all 2 2 Comments reply arch commented Oct 12, 2017 reply Follow Share why 2^5? biased formula is (2^(n-1) -1) "To calculate the bias for an arbitrarily sized floating point number apply the formula 2k−1 − 1 where k is the number of bits in the exponent." https://en.wikipedia.org/wiki/Exponent_bias plz correct if i m wrong 1 votes 1 votes Deepthi_ts commented Oct 12, 2017 reply Follow Share you are rite thanks for correcting me 0 votes 0 votes Please log in or register to add a comment.